Daily puzzles/problems.

15 trees?

Quote:

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Originally Posted by Scheherazade

15 trees?

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That was my guess, as well. However, the father had planted even fewer than 15 trees...

Is this going to involve a Star of David?


Edit: Yeah, it is. I just drew it. 10.


Edit again: imagine a tree at each point and each intersection.


http://upload.wikimedia.org/wikipedi..._David.svg.png

Oops. I miscounted. 11

4 trees maybe !

Quote:

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Originally Posted by MarkBastable

Is this going to involve a Star of David?


Edit: Yeah, it is. I just drew it. 10.


Edit again: imagine a tree at each point and each intersection.


http://upload.wikimedia.org/wikipedi..._David.svg.png

Oops. I miscounted. 11

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Quote:

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Originally Posted by hoope

4 trees maybe !

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Well, the correct answer is somewhere between Mark and hoope's answers.

Mark, that one has six rows?

10 with a five-sided star?

Quote:

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Originally Posted by Scheherazade

Mark, that one has six rows?

10 with a five-sided star?

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That's right.

Yeah, you're right.

I envisaged a Star of David (first message).

Drew a five-pointed star and counted the nodes (second message)

Then Googled 'Star of David' and linked it (third message).


My excuse is that I was distracted by Steve Jobs buggering up my iPhone with an update from beyond the grave.

God, I hate Apple. If my company didn't insist on me using an iPhone, I'd toss this thing out of the window,

Have to admit, I was considering a triangle (after my initial pentagol failed) until Mark's post.

A quick one:

You are on your way to the market with some gold coins in your pocket; however, you need to cross nine bridges before you reach your destination and there is a troll sitting under each bridge... They greedily ask for half of each passer's coin possession but, being somewhat good-hearted trolls still, they return one coin back.

How many coins do you need to have at the beginning of your journey so that you are left with at least two coins when you arrive at the market?

PS: No word games. Straight forward maths.

While my phone is in triage, I'll think about this in print.

So, in order to have two after the ninth bridge, you have to have three after the eighth bridge, because the troll will take....hang on...how's he going to take half of three?

So you have to have four. He takes two, gives one back, so you've got three after the ninth bridge, which fulfils the 'at least two' requirement.

To have four after the eighth bridge, you have to have six after the seventh bridge, because the troll will take three and give you one back.

To have six after the seventh bridge, you have to have ten after the sixth bridge, because the troll will take five and give you one back.

So - 18 after the fifth.

Okay, now i've either got to actually work it out, or - which would be much more fun - come up with a formula that works for any number of bridges.

Essentially, the number of coins you need for any bridge is 2 to the power of the number of the bridge (taking the last as bridge 0, and the penultimate bridge as bridge 1), plus two more coins.

I think.

That would mean it's (two to the power of eight) plus two.

So I think it's 258. It would be cowardly of me now to actually work out whether I'm right by going through the bridges one by one.

Quote:

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Originally Posted by billl

That's right.

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Well I thought the trick is how u read it ...
But, Bill when u said in the hint " five rows and four trees each " that confused ! Coz there is no EACH mentioned in the puzzle words when u read it !

Good one ... And good job Mark & Scher :)

Quote:

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Originally Posted by hoope

Well I thought the trick is how u read it ...
But, Bill when u said in the hint " five rows and four trees each " that confused ! Coz there is no EACH mentioned in the puzzle words when u read it !

Good one ... And good job Mark & Scher :)

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It's true there's lots of puzzles like this that have a trick reading--it might've been better if I had put "each" in both places (I almost left it out entirely, glad I thought to put it in...!)

Quote:

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Originally Posted by MarkBastable

While my phone is in triage, I'll think about this in print.

So, in order to have two after the ninth bridge, you have to have three after the eighth bridge, because the troll will take....hang on...how's he going to take half of three?

So you have to have four. He takes two, gives one back, so you've got three after the ninth bridge, which fulfils the 'at least two' requirement.

To have four after the eighth bridge, you have to have six after the seventh bridge, because the troll will take three and give you one back.

To have six after the seventh bridge, you have to have ten after the sixth bridge, because the troll will take five and give you one back.

So - 18 after the fifth.

Okay, now i've either got to actually work it out, or - which would be much more fun - come up with a formula that works for any number of bridges.

Essentially, the number of coins you need for any bridge is 2 to the power of the number of the bridge (taking the last as bridge 0, and the penultimate bridge as bridge 1), plus two more coins.

I think.

That would mean it's (two to the power of eight) plus two.

So I think it's 258. It would be cowardly of me now to actually work out whether I'm right by going through the bridges one by one.

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Perhaps you have to have 2 coins at the last bridge. He takes one and gives you one back. (A bit like VAT. ) In fact if that's right, you only need two coins when you set out, as each troll will take one and give you one back. Remember Trolls are fiscally inept.

HA!

Just like old times.

Quote:

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Originally Posted by prendrelemick

Perhaps you have to have 2 coins at the last bridge. He takes one and gives you one back. (A bit like VAT. ) In fact if that's right, you only need two coins when you set out, as each troll will take one and give you one back. Remember Trolls are fiscally inept.

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Oh, *^$£*.