rotor
...would not be the odd-one-out.
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rotor
...would not be the odd-one-out.
Gland, as all others can be typed on a single line of a qwerty keyboard.
What do the following states (listed alphabetically) have in common?
Alaska
Arizona
California
Connecticut
Hawaii
Illinois
Kentucky
Maine
Minnesota
New Hampshire
New Mexico
Oregon
South Dakota
Texas
Washington
No idea. They all have 2 or more vowels?
Yes they do, but that's not it.
Have they all got a watery boundary.
Only if you include rivers, Mick.
(at least there are OTHER states with pretty obvious water boundaries that aren't included in the list, so...)
Gun laws, politics, and order of statehood are also not yielding any obvious reasons for this grouping of states.
Hint: If you were looking at a list of all fifty states, it might be obvious.
I did too. And I'm an American citizen.
EDIT (I'm looking at an alphabetical list, though. Is that right, or is it the wrong kind of list?)
2.Alaska
3.Arizona
5.California
7.Connecticut
11.Hawaii
13.Illinois
17.Kentucky
19.Maine
23.Minnesota
29.New Hampshire
31.New Mexico
37.Oregon
41.South Dakota
43.Texas
47.Washington
They are the prime numbered states when alphabetically listed and numbered.
.....wouldn't it be great if that weren't the right answer but just a coincidence?
We all know there is no such thing as coincidence, Mark.
All right, here is the next one, which I tried to adopt from a Mensa puzzle. Hope it works.
Out of the seven PMs in my Inbox, Mark's is immediately before Papaya's. Bill's is between Mystry's and Mick's. Iamnobody's is immediately after Jajdude and there are two people between Iamnobody's and Mystry's. Mystry's is immediately after Papaya's.
From the top of the list, what is the order of PMs?
jaj
Iam
Mark
Papaya
Mystry
Bill
Mick
Yes, that is the correct answer. Bill also PMed it to me on Friday so whoever would like to go next :)
(I'm sorry that I did not reply sooner.)
Go ahead billl, if ya got one.
A blacksmith has six sections of chain, each with four links. If it takes him 20 seconds to open and close a link with his tools, what is the minimum amount of time he would need to make one length of chain out of these six sections?
100 seconds? That can't be right - it's too straightforward.
Yep, that's right. Too straight-forward. (That is, 100 seconds is not the correct answer.)
80 seconds. he breaks up one of the sections to join the five others.
That's it, Mick. (I'd seen this one in a couple books previously)
Oh gawd!
Right, time to scrape the bottom of a really old barrel.
How can 4 be half of 5.
Reckon it has nothing to do with Roman numerals?
Nice work, jajdude. I toyed with Roman numerals for a couple seconds, but not long enough for it to hit me.
An iron clad ivy league question this!
I really wish I could do something with 150 A.D.
Wait, wait, wait - where are we now? Jajude thinks he might know. Bill assumes jajude knows. Mick is giving clues that imply jajude's right. Bill's working on variations around the same theme. With all those clues, anyone with a few minutes could work it out, one assumes.
Can we just kill this one - someone give the answer, accept a smattering of applause - and move on?
[quote=
So, four = IV and that's half of FIVE (haha, Fe for iron, just got that hint too)
ok
Your turn jajdude.
I've got one I found tough, required some playing with digits 0 to 9, though two of them are not used. Will need some paper for this one I reckon.
Replace each different letter with a different digit to make
SEND + MORE = MONEY
Yeah, good one.
s=9
e=5
n=6
d=7
m=1
o=0
r=8
y=2
_9567
+1085
10653
I'm guessing there aren't any other solutions, but I didn't actually try it out for r=(something besides 8).
OK, unless I was dumb enough to triple-check my solution to the previous one incorrectly three straight times, here's the next puzzle, which it is my responsibility to provide.
The Wogged Pursuit of Perfection
In a completely different bubble of the Multi-verse that we lovingly refer to as "M", there is another universe with a similar type of cosmology, ruled over (created, in fact) by a deity known as "Gow". (But he's always been "Pat" to his deity-type-friends.)
Anyhow, Pat was never much for surprises, variety, or anything like that, but he was VERY good at one thing, and that was taking care of business promptly. For Pat, creating an entire planet in a week was a little behind the pace--he managed to create whole planetary systems in that much time. When he finally settled down to business, this is how it went:
For his first solar system, he built one star (sun) with one planet that had one moon. The next week, he built another star (always just the one star per system), but this time he was able to give it two planets, each with one moon. In the next system he built, he put three planets around the star, each planet having its own boring ONE moon orbiting it. And Pat stuck to this formula, oh yes, rigidly, steadily producing solar systems that were gradually (and very predictably) larger than previous ones.
After one year (weeks and years are "Earth years" calculated via atomic clock, for the purposes of this puzzle) Pat stopped. How many planetary bodies (stars, planets, and moons) combined did he have after 52 weeks of building them?
At the half way point on week twenty six he will make 1 sun 26 planets and 26 moons and that is his average output for the year. Thats 53 bodies times 52 weeks, which is 2756. However my maths prowess is legendary - For all the wrong reasons - so I've probably done it wrong.
Yes, not quite right. You've shown all the necessary brilliance, and have made a nice presentation of the technique that makes it all so elegant, of course. Just a little bit off. (Lucky for me!)
2756 + 52 stars ?