Please try these questions and test yourself

[Pensive]

Question 1: Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time Jason and Melvin started from Town B and walk towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B?

Question 2: Find the area, in square centimetres of a rectangular strip of board 3.8 m long and 75 mm wide.

Question 3: As many 8-cm diameter discs as possible are cut from a sheet of rectangular cardboard measuring 170 cm by 90 cm. Find the area of the sheet that if left?

~ I will love to hear what answers you got! Even if you are unable to solve these questions, please give a response. It will mean that other people were not able to do these questions like me. :D And if you are able to do it, it means that I have a very poor brain.

Virgil, Papaya and others who have specially read Mathematics and are reading it, I will love to hear especially from you. Tell us your answers and you can show us the solution as well if possible. :D

Thanks, I just found it interesting to share these questions with all of you.

[SleepyWitch]

SleepyWitch hates maths.. she's even too impatient to read the questions properly... but here's another good one:

one and a half chickens lay one and a half eggs in one and a half days. how many eggs do you get from 4 (whole) chickens in 9 days? er right... i've managed to figure it out, but I'll have to look up the solution again, so take your time

[smilingtearz]

100 -75 no wait.. um... 3.8*75 ... *trying to calculate*
urgh! i quit!!

[Virgil]

Question 1: Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time Jason and Melvin started from Town B and walk towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B?

Question 2: Find the area, in square centimetres of a rectangular strip of board 3.8 m long and 75 mm wide.

Question 3: As many 8-cm diameter discs as possible are cut from a sheet of rectangular cardboard measuring 170 cm by 90 cm. Find the area of the sheet that if left?

~ I will love to hear what answers you got! Even if you are unable to solve these questions, please give a response. It will mean that other people were not able to do these questions like me. :D And if you are able to do it, it means that I have a very poor brain.

Virgil, Papaya and others who have specially read Mathematics and are reading it, I will love to hear especially from you. Tell us your answers and you can show us the solution as well if possible. :D

Thanks, I just found it interesting to share these questions with all of you.


I don't have time right now at work, Pensy. I'll do it tonight when I get home.

[Helga]

I tried it but couldn't figure it out.... I took an IQ test two years ago and the professional who went over it told me that I'm 'blind' on math, it's similar to confuse letters, but I confuse numbers... this would be the reason why I have been failing in math every year since I was 13....

At least I tried... that has to 'count' for something....

[Boris239]

Q1
it is 37800 m
let's assume that time be4 Steven met jason is t
so 100t+80t=x where x is the distance
180t=x
at the same time Melvin passed 75t
So the second equation is 100(t+6)+75(t+6)=x
175t+1050=x=180t
5t=1050
t=210 so x=180*210=37800

[Boris239]

Q2: 3.8 m=380 cm
75 mm=7.5 cm
Area=380 *7.5=2850 cm^2

[ShoutGrace]

At least I tried... that has to 'count' for something....

:lol: :lol: :lol:

[Pensive]

Thanks everyone!

Witch, I can't even answer this one. It is night here and I am getting sleepy. (Where is Night by the way?)

Thanks Helga for trying. Virgil, I will look forward to it. I hope that you are doing well!

[Boris239]

For Q3 I'm not sure but I think that we can cut 21*11=231 discs. There area is 231*pi*16=3696*pi
So the area left is 170*90-3696*pi=15300-3696*pi

[Pensive]

Q1
it is 37800 m
let's assume that time be4 Steven met jason is t
so 100t+80t=x where x is the distance
180t=x
at the same time Melvin passed 75t
So the second equation is 100(t+6)+75(t+6)=x
175t+1050=x=180t
5t=1050
t=210 so x=180*210=37800

Oh yeah, that's very right. :thumbs_up
*am not sure about the other one*

[Pensive]

Boris, Is Math one of your major subjects?

[Boris239]

Here is a good one:
two old friends are meeting:
1: I have 3 children
2: How old are they?
1: The product of their ages is 36
2: It's not enough info
1: The sum of their ages is the number of windows in the nearby house:
2: Still not enough info:
1: My eldest is redhead
2: Oh, now I know

How old are the children?

[Boris239]

Boris, Is Math one of your major subjects?

Yes, I'm doing my Masters in it now

My 100th post :banana:

[Pensive]

Congratulations on your 100th post, Boris!

[ClaesGefvenberg]

Hey, this is fun :D
For Q3 I'm not sure but I think that we can cut 21*11=231 discs. How about 20*6 + 21*6=246 discs? If you move every second row vertically and let the discs slide sideways you will gain an extra row while losing one disc from the moved rows. This would give you 246*pi*16=12365 cm2 of disc area. So: 15300-12365= 2934 cm2.

Do I get a cigar?

/Claes

[Pensive]

I don't know the answers of other questions by myself yet.

[papayahed]

Darn it Pen!!!!!!! Now I have to try these out - my boss isn't going to like that!!

[Mililalil XXIV]

If there are only half as many good Marriages as there are people in them, and some people are celibate, how many people are not in good Marriages?

If I'm a Mister, and you're a Mister, and all good people are Misters, how many people are good?

Does Pensive have the mathematical formulae for these good questions?

[papayahed]

Hey Boris, I got something different for the first one: The time it Jason and Melvin to be 600m apart is 120 minutes. In 120 minutes Steve has walked 12000m and Jason has walked 9600 m which will equal 21600m when they meet.


Question 2: 2850 cm^2

Question 3: Still thinking, so far I have 3750cm^2 but I just read CJ's.

[Boris239]

papayhead, why there should be 600m between Jason and Melvin, when Jasom and Melvin meet?
I checked my answer it fits
t=210 Steve is 210*100=21000 from A
Jason is 210*80=16800 from B
Melvin is 210*75=15750 from B
So there are 1050 m between melvin and Steve. Their speed of approaching is 100=75=175
So it will take them 1050/175=6 m to meet

[Boris239]

If there are only half as many good Marriages as there are people in them, and some people are celibate, how many people are not in good Marriages?

If I'm a Mister, and you're a Mister, and all good people are Misters, how many people are good?

Does Pensive have the mathematical formulae for these good questions?

The answer to the first question is thera are no people not in good marriages

The second problem doesn't have a solution- it is impossible to say how many people are good

[papayahed]

Jason and Melvin don't meet.

[Boris239]

Jason and Melvin don't meet.

I know. So?

[papayahed]

oh duh. If it takes Steve six minutes to meet Melvin after he passed Jason wouldn't that be 600m that Steve has walked since his pace is 100m/min.

[Boris239]

But Melvin was alo walking at that time and passed 6*75=450 m, so the distance is not 600 but 600+450=1050

[papayahed]

Yeah, somehow that little part feel out of my equation. I did say I was getting dumber.

[Boris239]

I do really stupid mistakes regularly, but because recently I started tutoring kids for SAT math the number of these mistakes diminished greatly( at least in elementary algebra)

[AimusSage]

That's the good thing about teaching, you learn so much from it. Not that I am a teacher, but that's why I know so little. :)

[ClaesGefvenberg]

To illustrate what I tried to describe in words: If you stack the discs like the bottles in this picure you can cram 246 of them in...

/Claes

[Boris239]

Yes, it seems that you are right. what about this one:
two old friends are meeting:
1: I have 3 children
2: How old are they?
1: The product of their ages is 36
2: It's not enough info
1: The sum of their ages is the number of windows in the nearby house:
2: Still not enough info:
1: My eldest is redhead
2: Oh, now I know

How old are the children?

[formality hater]

[QUOTE=Pensive]Question 1: Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time Jason and Melvin started from Town B and walk towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B?

Question 2: Find the area, in square centimetres of a rectangular strip of board 3.8 m long and 75 mm wide.

Question 3: As many 8-cm diameter discs as possible are cut from a sheet of rectangular cardboard measuring 170 cm by 90 cm. Find the area of the sheet that if left?


For Q1 graphical solution is more helpful but I can give you the answers of Q2 and 3.Here you go,
Q2:Area=L*w
=3.8*75/1000(converting 75mm to SI unit-m)
=3.8*0.075
=0.285m2
Q3:Area of the discs=pi*radius(square)
=3.14*(8/2)square
=3.14*16
=50.24cm2
Are of rectangular sheet=170*90
=15300cm
Area of the sheet left=15300-50.24
=15249.76cm2
I think they are correct. :banana:

[Pensive]

Thanks FH (short of formality-hater)

Oh yeah, these should be correct by the procedure.

[bazarov]

I agree with Boris, it's definitly 37 800m distance.
S=100 m/min
J=80 m/min
M=75m/min
(1) S and J ... 100*y(from A)+80*y(from B)=z
(2) S and M... 100*y(from A)+100m/min*6min + 75*y(from B)75m/min*6min=z

so, (1)=(2) and then it equals

5*y=1050, y=210

100*210+80*210=37 800

Children ages, is it a joke or what?? Can two of them be same ages, and why is so important that one is redhead?

[vrianto3]

Question 1: Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time Jason and Melvin started from Town B and walk towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B?

Question 2: Find the area, in square centimetres of a rectangular strip of board 3.8 m long and 75 mm wide.

Question 3: As many 8-cm diameter discs as possible are cut from a sheet of rectangular cardboard measuring 170 cm by 90 cm. Find the area of the sheet that if left?

~ I will love to hear what answers you got! Even if you are unable to solve these questions, please give a response. It will mean that other people were not able to do these questions like me. :D And if you are able to do it, it means that I have a very poor brain.

Virgil, Papaya and others who have specially read Mathematics and are reading it, I will love to hear especially from you. Tell us your answers and you can show us the solution as well if possible. :D

Thanks, I just found it interesting to share these questions with all of you.

When I was still in high school, I had solved math problems similar to these three within minutes - only using pencil and paper. Now that I have passed 'higher education' and actually work in the real world equipped with sophisticated computers, you'd think I should solve those within seconds.

[long sigh]

There must be something wrong with my computer ;)

"He who replies to words of Doubt, Doth put the Light of Knowledge out"